- This is an assessment test.
- To draw maximum benefit, study the concepts for the topic concerned.
- Kindly take the tests in this series with a pre-defined schedule.
Number System: Level 2 Test -12
Congratulations - you have completed Number System: Level 2 Test -12.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%%
Your answers are highlighted below.
Question 1 |
Philip, Tom and Brad start jogging around a circular field and complete a single round in 18, 22 and 30 seconds respectively. In how much time will they meet again at the starting point?
8 minutes 15 seconds | |
21 minutes | |
16 minutes 30 seconds | |
12 minutes |
Question 1 Explanation:
They would meet after LCM(18,22,30)= 990 secs = 16 mins 30 secs.
Correct option is (c)
Correct option is (c)
Question 2 |
In a two digit number the digit in the unit’s place is twice the digit in the ten’s place and the number obtained by interchanging the digits is more than the original number by 27. What is 50% of the original number?
36 | |
63 | |
48 | |
18 |
Question 2 Explanation:
Let the digits be x(units) and y(tens) respectively .
Possible cases:
On interchanging 36 we get 63 which is exactly 27 more than the original number.
Thus 50% of 36 = 18.
Correct option is (d)
Possible cases:
On interchanging 36 we get 63 which is exactly 27 more than the original number.
Thus 50% of 36 = 18.
Correct option is (d)
Question 3 |
The difference between a two digit number and the number obtained by interchanging the positions of its digits is 36. What is the difference between the two digits of that number?
4 | |
9 | |
3 | |
Cannot be determined |
Question 3 Explanation:
Let the number be of form 10x+y.
Thus ,
x+y= 4.
The possible cases are 40,31,22.
Only 40 satisfies the condition. Thus the correct answer is (a)
Thus ,
x+y= 4.
The possible cases are 40,31,22.
Only 40 satisfies the condition. Thus the correct answer is (a)
Question 4 |
On a particular day, sweets were to be equally distributed among 495 students of a school. However, on that particular day 396 students from a nearby school also joined them. Hence each student present on that day got four sweets less. How many sweets were distributed?
5445 | |
4950 | |
4455 | |
3960 |
Question 4 Explanation:
Let them originally receive x sweets each.
Total sweets distributed = 495x.
495x=(495+396)(x-4)
=> x=9
Thus total sweets = 495X9 =4455
Correct option is (c)
Total sweets distributed = 495x.
495x=(495+396)(x-4)
=> x=9
Thus total sweets = 495X9 =4455
Correct option is (c)
Question 5 |
The students present in an auditorium are asked to stand in rows. If there were 4 students extra in a row there would be 4 less rows. However, if 2 students were less in a row, there would be 4 more rows. The number of students present in the auditorium is
80 | |
96 | |
100 | |
128 |
Question 5 Explanation:
Let the number of students in each row be x and rows be y.
Thus xy =(x+4)(y-4)
xy=(x-2)(y+4)
x=8 and y=12
The number of students is = 8*12=96
Correct option is (b)
Thus xy =(x+4)(y-4)
xy=(x-2)(y+4)
x=8 and y=12
The number of students is = 8*12=96
Correct option is (b)
Once you are finished, click the button below. Any items you have not completed will be marked incorrect.
There are 5 questions to complete.
List |
