**Directions (Q. Nos. 1-4)** Study the following line graph to answer these questions.

Railway Time Schedule of an Express Train X Running Between City A and City H

a → Arrival of train

d→ Departure of train

A, B, C, D, E, F, G and H are cities through which the train runs.

a-d→ Indicates stoppage/halting of the train at the city station.

**Question 1:** The average speed of the train maintained between two successive stations was maximum between

(a) E-F

(b) F-G

(c) G-H

(d) Both G -H and F-G

**Question 2:** Between how many pairs of consecutive stations does the speed run below the overall average speed of the entire trip?

(a) 4

(b) 1

(c) 3

(d) 2

**Question 3: **If the train stops at each city for 30% more time, then at what time will it reach the city H after departing from City A as per schedule?

(a) Data insufficient

(b) 17 : 03

(c) 16 : 41

(d) 16 : 58

**Question 4:** The train begins its onward journey from City A and it is extended to beyond City H to a City M due to some unavoidable reason. The train starts its return journey immediately after it reached City M. The train returns with a speed of 90 km/h without any stoppages in between and reaches City A at 2 : 25 am. Find the distance between City H and City M.

(a) 40 km

(b) 90 km

(c) 70 km

(d) None of these

### Answers and Explanations

**Answer 1: (b)**

Therefore, the correct option is (b)

**Answer 2: (c)**

Overall average speed = 800/633 = 1.264 km/min

Hence, between stations B-C, D-E and G-H the speed of the train was less than the average speed of the entire journey. Correct option is (c)

**Answer 3: (c)**

New arrival time = 16:25 + 16 = 16:41 min

Correct option is (c).

**Answer 4: (d)**
Assuming the train starts its journey from M towards A at 16:25

Time taken to reach A from M= 24+2:25 – 16:25 = 10 hours.

Average speed = 90 Km/hr.

Total distance M-A = 90 × 10 = 900 Km.

Total distance A-H = 800 Km.

Therefore, Distance between H and M is 900-800 = 100 Km.

Correct option is (d)