*“Now, then, Mahesh, how old is Migo?” Anupama’s young man asked her brother. “Well, five years ago,” was the youngster’s reply, “sister was four times older than the dog, but now she is only three times as old.” Can you tell Migo’s age?*

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Migo’s present age is ten years and Anupama’s thirty years. Five years ago their respective ages were five and twenty-five. Remember that we said “four times older than the dog,” which is the same as “five times as old.”

The answer is 10 years.

“A is 4 times older than B” -> A’s age= 4* B’s age+B’s age;

“A is 4 times as old as B” -> A’s age= 4* B’s age

*According to my knowledge*

it should be 15 not 10 !!

If someone wants equations…

S is sister

M is migo

4 times older means 5 times old.

Five years back

(S-5)=5(m-5)

S-5=5m-25

S-5m=-20

Today, S=3m

Substitute 2 in 1, we get

3m-5m=-20

-2m=20

So m =10.

You are welcome.

As explained it’ good but pls share us method by equation.

15

i guess the answer is 15 not 10.

let migo’s (the dog) present age be x. so Sis = 3(x) [present age] . 5 years ago sis was 4 times as old as migo. So, sis – 5 = 4 (x – 5) . put sis as 3x and get your answer.

Can someone explain the question and solving procedure? I am not able to get the solution.

Thanks in advance!

Question is not clear.plz explain it.

please give appropriate solution.

its little bit complex

15

hey its 15