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Geometry and Mensuration: Level 2 Test 9
Question 1 |
Suface area of a cuboid is 22 cm2 and the sum of the lengths of all its edges is 24 cm. Length of each diagonal of the cuboid (in cm) is
145 | |
200 | |
122 | |
none |
Question 1 Explanation:
Let the length , width and height be l , w and h units respectivelyl+b+w=244=6lb+bw+lw=222=11Nowl2+b2+w2+2lb+2bw+2lw=(l+b+w)2l2+b2+w2+22=36l2+b2+w2=14√l2+b2+w2=√14
Question 2 |
A slab of ice 8 inches in length, 11 inches in breadth, and 2 inches thick was melted and re-solidified in the form of a rod of 8 inches diameter. The length of such a rod, in inches, in nearest to:
3 | |
3·5 | |
4 | |
4·5 |
Question 2 Explanation:
The volume of the ice slab =8X11X2
The volume of the rod (assuming length = h) =Πx42h = 8 x 11 x 2
h = 3.5
Correct option is (b)
The volume of the rod (assuming length = h) =Πx42h = 8 x 11 x 2
h = 3.5
Correct option is (b)
Question 3 |
Four friends start from four towns, which are at the four comers of an imaginary rectangle. They meet at a point which falls inside the rectangle, after travelling the distances of 40 m, 50 m and 60 m. The maximum distance that the fourth could have travelled is approximately:
67 m | |
52 m | |
22.5 m | |
Cannot be determined |
Question 3 Explanation:
Now we know that if we assume the length required =p resp,
then 50 x 40 = 60 x p
=> p = 50 x 40/60
=> p = 66.67
The correct option is (a)
then 50 x 40 = 60 x p
=> p = 50 x 40/60
=> p = 66.67
The correct option is (a)
Question 4 |
The length of a ladder is exactly equal to the height of the wall it is leaning against. H lower end of the ladder kept on a stool of height 3 m and the stool is kept 9 m away from the wall, the upper end of the ladder coincides with the top of the wall. Then, the height of the wall is:
12 m | |
15 m | |
18 m | |
11 m |
Question 5 |
An equilateral triangle and a regular hexagon have equal perimeters. The ratio of the area of the triangle and that of the hexagon is
1: 1 | |
2: 3 | |
3: 2 | |
3: 4 |
Question 5 Explanation:
Let the individual sides of the hexagon be 1 cm
Thus the perimeter =6 and the side of the equilateral triangle is 2cm.
Thus the area of the equilateral triangle = √3 x 4 = √3 cm.
Thus the area of the hexagon= {(6 x √3)/4} x 12 = 3/2√3
Thus the ratio of the triangle to hexagon is 2:3.
Correct option is (b)
Thus the perimeter =6 and the side of the equilateral triangle is 2cm.
Thus the area of the equilateral triangle = √3 x 4 = √3 cm.
Thus the area of the hexagon= {(6 x √3)/4} x 12 = 3/2√3
Thus the ratio of the triangle to hexagon is 2:3.
Correct option is (b)
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