The ages were as follows: Bunny, 3½ years; Geet, 1¾ year; Harpreet, 5¼ years; Chatur, 10½; years; and Jaspreet, 21 years.

Explanation: The equations that help us solve this riddle are as follows:

(The following is list of notations followed to solve the puzzle: A=Anant’s age at year 0 M=Mom’s age at year 0 D=Dad’s age at year 0 T=Tez Singh’s age today,

The problem gives us the following equations:

Ananti is 1/4 her mother’s age at T=0 A = 1/4*M……………………………………1 Presently, Ananti’s age (A+T) is 1/3 her father’s age (D+T) A+T = 1/3*(D+T)…………………………….2 Presently, Tez’s age (T) is 1/4 his mother’s age (M+T) T = 1/4*(M+T)………………………………….3 In 4 years, Tez’s age (T+4) will be 1/4 that of his father’s age (D+T+4)

T+4 = 1/4*(D+T+4)……………………………….4

Now we have T+4 =1/4*(D+T+4)

T+4=(D+T+4)/4 T= {(D+T+4)/4}-4 T=(D+T-12)/4…………………………………5

From 5 and 3 (if L.H.S. is equal then R.H.S. side is also equal)

(D+T-12)/4 = ¼ (M+T)

D = M+12……………………………………..6

From 3, M= 3T

So, D= 3T+12………………………………….7

Putting the value of M in 1, we have A = ¾T……………………………8

From eq. 2 A+T= D/3 +T/3 3A+3T=D+T 3A= D+T-3T

Put value of D from 7in this: 3A= 3T+12+T-3T A=(T+12)/3………………………………………9 From 8 and 9 3/4T= (T+12)/3 By solving T= 9.6

Now we solve these last 2 equations for M & D respectively, and substitute into the first 2 equations will result in 2 equations in terms of A & T: A = 3/4*T A = 1/3*(T+3T+12)

Solving for T = 9.6 years Tez Singh’s age must have been nine years and three-fifths.